An electric iron of resistance 20w takes a current of 5 A. Calculate the heat developed in 30s.
Answers
Answered by
2
Given that Resistance(R) = 20 Ω, Electric current (I)= 5 A and time(t)= 30 s
Now we know that H= I2Rt
= 5×5×20×30
= 15000J=1.5×104J
∴ The heat developed in 30s is 1.5×104J
Answered by
2
Answer: 5^2×20
=25×20
=500 j
Explanation:
Power = 20watt
Current = 5A
Time = 30sec
Formula:
H=I×I×R×t
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