An electric iron of resistance 25 ohm takes a current of 4
a. calculate the heat developed in 2 minutes
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Hii...
The heat developed is the work done
So , using relation, H=(I)2 ×R×T
first we have to change time in seconds,
T= 2 min=120 s
(I)2 = 4×4 =16A
R= 25 ohm
Hence, Heat= 120×16×25
=48000J
or 48 KJ
Hope it helps...
Plzz mark as brainliest answer....
The heat developed is the work done
So , using relation, H=(I)2 ×R×T
first we have to change time in seconds,
T= 2 min=120 s
(I)2 = 4×4 =16A
R= 25 ohm
Hence, Heat= 120×16×25
=48000J
or 48 KJ
Hope it helps...
Plzz mark as brainliest answer....
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