Question

 An electric iron rated 1 kilowatt operates 10 hours per day. calculate the energy consumed in 30 days?​

Answer 1

Answer:

300 units

Explanation:

as we know that energy=power*time

so =1*30*10=300 units

Answer 2

Answer:

It will consume 1.08 × 10⁹ J of energy.

Explanation:

Given that the electric iron is rated  1 kilowatt. This means it consumes 1 kilowatt of energy in 1 hour.

Step - 1

We will first calculate how much energy it will consume in 10 hours.

Since it is given that it operates for 10 hours each day.

Energy consumed = $1kW\times 10\ hr = 1000\ J/s \times36000s = 36000 \ kJ$

So it will consume 36000 kJ of energy.

Step - 2

Next, we need to calculate the amount of energy consumed in Joule in 30 days.

Energy consumed = $36000\ kJ \times30 = 1080000\ kJ = 1.08\times 10^9 J$

So it will consume 1.08 × 10⁹ J of energy.

#SPJ3