An electric iron rated as 750W and 220V. calculate that-
i) Current flowing through it
ii) It's resistance when in use
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Answer:
(i) Power = Voltage × Current
Let, the current passing through the bulb be I
750 = 220 X I
I = 750 / 220
= 3.41 A
Therefore, 3.41 A current passes through the electric iron.
(ii) Electric power is related to voltage and resistance as:
Power = (Voltage) power 2 / R
R = 220 x 220 / 750
= 64 .53 ohm
Therefore, the electric iron offers 64.53Ω resistance when in use.
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