Physics, asked by ranjan6899, 7 months ago

An electric kettle consume 1 kilowatt of electric power operated at 220 volt a fuse wire of what rating most used for it ?​

Answers

Answered by MystícPhoeníx
31

Given:-

  • Power ,P = 1 Kw

  • Voltage ,V = 220v

To Find:-

  • Current ,I

Solution:-

Converting the Power into Watt

1Kw = 1000 W

As we know that

• P = VI

• I = P/V

Substitute the value we get

→ I = 1000/220

→ I = 4.54 A

Therefore, the rating of fuse wire must be greater than 4.5 A i.e. 5 A

Additional Information!!

Potential Difference: The potential difference between two point in an electric circuit carrying some current as the work done to move a unit charge from one point to the other.

Potential difference = Work done /Charge.

V = W/Q

here

V is the potential difference

W is the work done

Q is the charge

✧ SI unit of electric potential energy is volt (V).

✧ 1 volt : The potential difference between two points in a current carrying conductor when one joule of work is done to move a charge of one coulomb from one point to other.

1 Volt = 1Joule/1Coulomb

Answered by Mister360
21

Answer:

Given :-

Power = 1 Kilowatt

Voltage = 220 vatt

To find :-

Current

Solution :-

First we have to convert Kilowatt into watt

As we know that

1 Kilowatt = 1000 watt

According to Question

 \bold {current \:  =  \frac{power}{voltage}}

Putting values

current \:  =  \frac{1000}{220}

  \huge \bold {c\:  = 5.4 \: ampere}

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