An electric kettle consume 1 kilowatt of electric power operated at 220 volt a fuse wire of what rating most used for it ?
Answers
Given:-
- Power ,P = 1 Kw
- Voltage ,V = 220v
To Find:-
- Current ,I
Solution:-
Converting the Power into Watt
1Kw = 1000 W
As we know that
• P = VI
• I = P/V
Substitute the value we get
→ I = 1000/220
→ I = 4.54 A
Therefore, the rating of fuse wire must be greater than 4.5 A i.e. 5 A
Additional Information!!
Potential Difference: The potential difference between two point in an electric circuit carrying some current as the work done to move a unit charge from one point to the other.
Potential difference = Work done /Charge.
V = W/Q
here
V is the potential difference
W is the work done
Q is the charge
✧ SI unit of electric potential energy is volt (V).
✧ 1 volt : The potential difference between two points in a current carrying conductor when one joule of work is done to move a charge of one coulomb from one point to other.
1 Volt = 1Joule/1Coulomb
Answer:
Given :-
Power = 1 Kilowatt
Voltage = 220 vatt
To find :-
Current
Solution :-
First we have to convert Kilowatt into watt
As we know that
1 Kilowatt = 1000 watt
According to Question
Putting values