Question

An electric kettle for use on a 230 V supply is rated at 3000 W. For safe working, the cable connected to it should be able to carry at least:; A. 2 A; B. 5 A; C. 10 A; D. 15 A

Answer 1

Explanation:

refer to the attachment....

Answer 2

Answer:

Explanation:

Potential difference,V=230V

Power,P=3000W

We know that,

P=VI=> 3000=230×I

I=3000/230=13.04amp

Therefore, the cable should carry current not exceeding 13.04amp.

The nearest answer is 15A

So,OPTION (d) 15A