An electric kettle is rafted at 25w.Calculate
The quantity of heat generated in 2s
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Answer:Energy consumed by electric kettle in 9.5 min =Pt=(2.5×10^3
)×(9.5×60)=14.25×10^5
J
Energy usefully consumed =msΔT=3×(4.2×10^3
)×(100−15)=10.71×10^5
where s=4.2J/g° c= specific heat of water and boiling point temp=100°c
Heat lost =14.25×10^5
−10.71×10^5
=3.54×10^5
Explanation:Please mark the answer as brainliest
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