Question

An electric kettle is rated 12kW. How many joules of energy are transferred in 20 seconds?

Answer 1

Explanation:

b Question 3.

Give the steps you will use to separate the variables and then solve the equation:

(a) 3n – 2 = 46

(b) 5m + 7 = 17

(c) 20p3=40

(d) 3p10=6

Solution:

(a) 3n – 2 = 46

⇒ 3n- 2 + 2 = 46+ 2 (adding 2 to both sides)

⇒ 3n = 48

⇒ 3n + 3 = 48 ÷ 3 sh vi 6db

Answer 2

Answer:

Power(W) = Heat(J) / Time(s)

12kW = 12000W

t = 20s

12000W × 20s = Heat

240000J

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