Question

an electric kettle is rated at 25w. calculate the quantity of heat generated in 2 seconds​

Answer 1

Answer:

$\huge \boxed{ \fcolorbox{red}{orane}{easy \: bro}}$

Energy consumed by electric kettle in 9.5 min =Pt=(2.5×10

3

)×(9.5×60)=14.25×10

5

J

Energy usefully consumed =msΔT=3×(4.2×10

3

)×(100−15)=10.71×10

5

where s=4.2J/g

o

C= specific heat of water and boiling point temp=100

o

C

Heat lost =14.25×10

5

−10.71×10

5

=3.54×10

5

Answer 2

Answer:

50J

Explanation:

GIVEN : a) Power of electric kettle = 25W

TO FIND : heat generated in 2 seconds

we know that ; a) H = I²RT

                        b) and power = I²R

THEREFORE  = H = PT

putting the value getting the answer we get :

⇒ (25)*(2 ) = 50 Joule

answer of this question is  50 J

#SPJ2