Physics, asked by vikkubindu, 10 months ago

An electric kettle of 15 watt works for to our daily and 40Watt bulb works for 10 hour daily calculate the energy consumed in a day and what is the cost of running it in the month of June at the rate of

Answers

Answered by gamerchiru395
0

Answer:-

We know energy = power*time

For bulb1 :-

= 15*2=30w

30 watts per day

30*30=900w

Change watts to kilowatts :-

= 900/1000=0.9Kwh

For bulb 2 :-

= 40*10=400w

400 watts per day

400*30=12000w

Change watts to kilowatts :-

= 12000/1000=12Kwh

Add both 12+0.9 = 12.9Kwh

= 12.9units

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