Question

an electric kettle of 1500 omh work on 230 v supply a] write the energy taking place in the electic kettle b] calculate energy consumed when heater work for one hour

Answer 1

Answer:

$\blue{\mathfrak{\underline{\large{Given}}}:} \\ resistance\:of \: electric \: kettle(R) = 1500 \: Ω \\ potential \: difference(V) = 230 \: V \\ time(t) = 1 \: hrs \\ \blue{\mathfrak{\underline{\large{To \: find}}}:} \\ a] write \: the \: energy \: taking \: place \: in \: the \: electic \: kettle. \\ b] calculate \: energy \: consumed \: when \: heater \: work \: for \: one \: hour. \\ \blue{\mathfrak{\underline{\large{Finding}}}:} \\ a) \: Electric \: energy \: converted \: into \: heat \: energy \\ b) \: power(p) = \frac{ {V}^{2} }{R} = \frac{ {(230)}^{2} }{1500} = \frac{52900}{1500} watt \\ \\ = \frac{529}{15} \times \frac{1}{1000} kw \\ \\ Energy \: consumed \: by \: heater \: in \: 1hour \\ = p \times t \\ = \frac{529}{15} \times \frac{1}{1000} kw \times 1h \\ \\ = 0.035 \: kwh \\ \\ \red{\mathfrak{\underline{\large{Hope \: It \: Helps \: You }}}} \\ \green{\mathfrak{\underline{\large{Mark \: Me \: Brainliest}}}}$