Physics, asked by smirtimaskara, 1 year ago

An electric kettle of 500 W is used to heat water every day for 2 hours. calculate the number of units of electrical energy consumed by it in 10 days.

Answers

Answered by saitejassb
127
POWER=500W =0.5KW
Time=2 Hrs
Electrical Energy=Power * Time
=0.5*2
=1KWh or 1Unit
Electrical energy in one day=1unit
Electrical energy in 10 days =1unit * 10 = 10 units
Answered by VineetaGara
6

Given,

Power consumption of an electric kettle = 500 watts

Total time of operation of the kettle = 2 hours per day

To find,

Total units of energy consumed by the electric kettle, in 10 days.

Solution,

We can simply solve this numerical problem by using the following process:

Mathematically,

Power (P)

= Energy consumed (E) ÷ Time (T)

=> Energy consumed (E) = Power (P) x Time (T)

Now,

Total units of energy consumed in one day by the electric kettle

= Power (P) x Time (T)

= 500 W x 2 hour

= 1000 Wh = 1 kWh = 1 electrical unit

(Since 1 kWh = 1 electrical unit)

So, the total units of energy consumed by the electric kettle in 10 days

= (units of energy consumed in one day) x 10

= 1 electrical unit x 10

= 10 electrical units

Hence, a total of 10 electrical units of energy is consumed by the electric kettle, in 10 days.

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