An electric kettle of 500 W is used to heat water every day for 2 hours. calculate the number of units of electrical energy consumed by it in 10 days.
Answers
Time=2 Hrs
Electrical Energy=Power * Time
=0.5*2
=1KWh or 1Unit
Electrical energy in one day=1unit
Electrical energy in 10 days =1unit * 10 = 10 units
Given,
Power consumption of an electric kettle = 500 watts
Total time of operation of the kettle = 2 hours per day
To find,
Total units of energy consumed by the electric kettle, in 10 days.
Solution,
We can simply solve this numerical problem by using the following process:
Mathematically,
Power (P)
= Energy consumed (E) ÷ Time (T)
=> Energy consumed (E) = Power (P) x Time (T)
Now,
Total units of energy consumed in one day by the electric kettle
= Power (P) x Time (T)
= 500 W x 2 hour
= 1000 Wh = 1 kWh = 1 electrical unit
(Since 1 kWh = 1 electrical unit)
So, the total units of energy consumed by the electric kettle in 10 days
= (units of energy consumed in one day) x 10
= 1 electrical unit x 10
= 10 electrical units
Hence, a total of 10 electrical units of energy is consumed by the electric kettle, in 10 days.