Physics, asked by amulrowdybby, 18 days ago

an electric kettle rated at 2.5w of mass 0.5kg contains 1.5 kg water at 20c the kettle is turned on abd the kettle and its contents are heated to 100c. the s.h.c of the metal the kettle is made of is 500j/kg c and the s.h.c of water is 4200j/kg C
A) calculate the total amount of heat energy needed
b) how long must the kettle be switched on for tk heat the kettle and water to 100c .give your answer in minutes to two significant figures
c) in practice it will take longer than this to boil the water in the kettle.explain why​

Answers

Answered by rahulkumar555hzp
0

Explanation:

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Answered by Crystalisme
0

Answer:

(a)Q=mcΔt

0.5*500*(100-20)+1.5*4200*(100-20)= 524 000 J

(b)t=Q/p = 524000/2500=209.6s

209.6/60=3.5mins

(c) because of the environmental factors like temperature or humidity .

Explanation:

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