Question

an electric lamp and a conductor of resistance 4ohm are connected in seris to 6V battery. the current drawn by the lamp is 0.25A. find the resistance of the electric lamp.

Answer 1

Answer:

Hello Dear,

Explanation:

Lamp :

Resistance , R1=?

Potential differences, V1=?

Current drawn, I1=0.25A

Other conductor :

Resistance , R2=4Ω

Potential differences , V2=?

Current drawn , I2=?

Resultant resistance, R=R1+R2

∴ Potential difference, V=6V

Current in the circuit , I=0.25A

∵I=I1=I2

∴V=IR

⇒R=VI=60.25=6×100425=24Ω

Now, R1+R2=R ⇒R1+4=24

∴R1=24−4=20Ω

hope this helps u

Answer 2

Explanation:

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