an electric lamp and a conductor of resistance of 4 ohm are connected in series to a 6v battery the current drawn by the battery is 0.5A. find the resistance of the lamp
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Answer:
Given:-
Resistance (R1) = 4ohm
Voltage = 6V
Current = 0.5A
To find:-
Resistance of electric lamp (R2)
Total resistance,
By applying V = IR
R = V/I
= 6/0.5
= 12ohm.
R2 = 12 - 4 = 8ohm
As they are connected in series
So, Req = R1+R2
= 4+8
= 12ohm.
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