Question

An electric lamp draws a current of 0.3 ampere and is used for 6 hours everyday for a month 30 days calculate the amount of charge that flows through the current everyday and for a month

Answer 1

we know that
$q = i \times t$
charged flow through the current for one day
$q = 0.3 \times 5 \times 60 \times 60 = 6480 \: columb$
For 30 days we get
$= 6480 \times 30 \\ = 1.94 \times {10}^{5} columb$

Answer 2

Explanation:

Explanation:GIVEN:

Explanation:GIVEN: Current (l) = 0.3 A

Explanation:GIVEN: Current (l) = 0.3 A Time (t) = 6 hours

Explanation:GIVEN: Current (l) = 0.3 A Time (t) = 6 hours = 6*60*60

Explanation:GIVEN: Current (l) = 0.3 A Time (t) = 6 hours = 6*60*60

Explanation:GIVEN: Current (l) = 0.3 A Time (t) = 6 hours = 6*60*60 TO FIND:

Explanation:GIVEN: Current (l) = 0.3 A Time (t) = 6 hours = 6*60*60 TO FIND: Charge(Q) =?

Explanation:GIVEN: Current (l) = 0.3 A Time (t) = 6 hours = 6*60*60 TO FIND: Charge(Q) =?

Explanation:GIVEN: Current (l) = 0.3 A Time (t) = 6 hours = 6*60*60 TO FIND: Charge(Q) =? I = Q\t

Explanation:GIVEN: Current (l) = 0.3 A Time (t) = 6 hours = 6*60*60 TO FIND: Charge(Q) =? I = Q\t Q = I * t

Explanation:GIVEN: Current (l) = 0.3 A Time (t) = 6 hours = 6*60*60 TO FIND: Charge(Q) =? I = Q\t Q = I * t = 0.3*6*60*60

Explanation:GIVEN: Current (l) = 0.3 A Time (t) = 6 hours = 6*60*60 TO FIND: Charge(Q) =? I = Q\t Q = I * t = 0.3*6*60*60 = 6480C

Explanation:GIVEN: Current (l) = 0.3 A Time (t) = 6 hours = 6*60*60 TO FIND: Charge(Q) =? I = Q\t Q = I * t = 0.3*6*60*60 = 6480CCharge flow through circuit for one day = 6480 C

Explanation:GIVEN: Current (l) = 0.3 A Time (t) = 6 hours = 6*60*60 TO FIND: Charge(Q) =? I = Q\t Q = I * t = 0.3*6*60*60 = 6480CCharge flow through circuit for one day = 6480 C =6480*30

Explanation:GIVEN: Current (l) = 0.3 A Time (t) = 6 hours = 6*60*60 TO FIND: Charge(Q) =? I = Q\t Q = I * t = 0.3*6*60*60 = 6480CCharge flow through circuit for one day = 6480 C =6480*30 =194400 C

Explanation:GIVEN: Current (l) = 0.3 A Time (t) = 6 hours = 6*60*60 TO FIND: Charge(Q) =? I = Q\t Q = I * t = 0.3*6*60*60 = 6480CCharge flow through circuit for one day = 6480 C =6480*30 =194400 C

Explanation:GIVEN: Current (l) = 0.3 A Time (t) = 6 hours = 6*60*60 TO FIND: Charge(Q) =? I = Q\t Q = I * t = 0.3*6*60*60 = 6480CCharge flow through circuit for one day = 6480 C =6480*30 =194400 C Charge flow through circuit for one month = 194400 C