Question

An electric lamp has resistance of 20 Ohm and conductor of 4 ohm resistance are connected to a 6 volt battery. Calculate the total resistance of the circuit and the current through the circuit.​

Answer 1

Aɴsᴡᴇʀ~

Given:-

• Resistance 1 (R1) = 20 Ohm
• Resistance 2 (R2) = 4 Ohm
• Voltage = 6V

To find:-

• Current

_____________

For resistance:-

➦ Total Resistance = R1 + R2

➦ Total Resistance = 20 Ohm + 4 Ohm

➦ Total Resistance = 24 Ohm

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For current:-

$\bigstar \: \bold {Current} = \frac{ \bold \red {voltage}}{ \bold \red {resistance}}$

$\bigstar \: \bold {Current} = \frac{ \bold \red {6 \: v}}{ \bold \red {24 \: ohm}}$

$\bigstar \: \bold {Current} = \bold \purple {0.25 \: amphere}$

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For potential difference:-

$\bigstar \: \bold {potential \: difference} = { \bold \orange{current}} \times { \bold \orange {resistance}}$

$\bigstar \: \bold {potential \: difference} = { \bold \orange{0.25}} \times { \bold \orange {20}}$

$\bigstar \: \bold {potential \: difference} = \bold \purple{5v}$

______________

Answer 2

☆Answer☆:-

a). the total resistance of the circuit =20Ω+4Ω=24Ω

b). The current through the circuit= current through the bulb= current through the conductor.

The current through the circuit=

the voltage of the battery/voltage applied

the current through the circuit = 6/24 amp

The current through the circuit = 0.25amp

Itzgirl45 ❤️