Math, asked by vvk64, 4 months ago

An electric lamp is marked 100W,220V' what do u understand by this? What current is taken by the lamp when it is connected to a 220v mains supply? What is the resistance of the lamp​

Answers

Answered by BrainlyEmpire
276

\red{\odot} Correct Question :

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  • \textsf{An electric lamp is marked 100 W, 220 V. It means that the electric lamp will consume 100 joule of energy per second when connected to a 220 V supply.}

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\green{\odot} Required Solution :

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  • \textsf{Given that the electric lamp is connected to a exactly 220 V mains supply. }

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\purple{\odot} So, We have

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  • \textsf{Potential difference, V = 220 v}

  • \textsf{Power, P = 100 W}

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  • \textsf{P = V I}

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\pink\bigstarWhere,

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  • \textsf{P = Power}

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  • \textsf{V = Potential difference}

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  • \textsf{I = Current}

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  • \textsf{⇒  100 = 220 × I}

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  • \textsf{⇒  10/22 = I}

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  • \textsf{⇒  5/11 = I}

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  • \textsf{⇒  I = 5/11 A}

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  • \textsf{Potential difference, V = 220 v}

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  • \textsf{Current, I = 5/11 A}

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\mathfrak{✴\;So, \;Resistance \;of \;the\; electric \;lamp \;can\; be calculated \;as,}

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  • \blue\bigstar\textsf{⇒  V = I R}

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\red\bigstarWhere,

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  • \blue\bigstar\textsf{R = Resistance}

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  • \textsf{⇒  220 = 5/11 × R}

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  • \textsf{⇒  220 × 11/5 = R}

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  • \textsf{⇒  44 × 11 = R}

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  • \textsf{⇒  R = 484 Ω}

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\mathfrak{✴\;Hence,\; When\; the\; electric \;lamp\; is\; connected\; to\; a\; 220\; v\; mains\; supply,}

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  • \orange\bigstar\textsf{Current drawn = 5/11 A}

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  • \green\bigstar\textsf{Resistance = 484 Ω}

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Answered by ItzInnocentPrerna
75

\Huge\mathbf\colorbox{orange}{{\color{black}{☆ANSWER☆}}}

\huge\bf\underline{\underline{\orange{GIVEN :}}}

\orange\bigstar An electric lamp is marked 100W, 200V.

\huge\bf\underline{\underline{\orange{TO \: FIND :}}}

\orange\bigstar What do you understand by this ?

\orange\bigstar What current is taken by the lamp when it is connected to a 220 V mains supply ?

\orange\bigstar What is the resistance of the lamp ?

\huge\bf\underline{\underline{\orange{SOLUTION :}}}

\orange\bigstar\bf{P = Power}

\orange\bigstar\bf{V = Potential \: Difference}

\orange\bigstar\bf{I = Current}

\bf{→100 = 220 \times I} \\ \\ \bf{→ \frac{10}{22}  = I} \\ \\ \bf{→ \frac{5}{11}  = I} \\ \\ \bf{→ I =  \frac{5}{11} A}

\orange\bigstar We will calculate the resistance of the electric lamp as V = I R,

\bf{→220 =  \frac{5}{11} \times R} \\  \\ \bf{→220  \times  \frac{11}{5} = R } \\  \\ \bf{→44 \times 11 = R} \\  \\ \bf{→R = 484 \: Ω}

\boxed{{\sf\orange{Hence, \: 5/11 A \: current \: is \: taken \: by \: the \: lamp \: when \: it \: is \: connected \: to \: a \: 220 \: V \: mains \: supply.}}}

\boxed{{\sf\orange{Hence, \: the \: resistance \: of \: the \: lamp \: is \: 484 \: Ω}}}

Hope it Helps Buddy ♥️

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