Question

an electric lamp is marked 25 Watt,220 volt it is used for 10 hours daily calculate 1) its resistance while glowing 2) energy consumed in Kwh per day

Answer 1

Here power of lamp is 25 Watt.
potential difference =220 volts

resistance =1936ohms

Energy consumed=0.25kwh

Answer 2

Answer: resistance while glowing is 1936 ohm

Energy consumed in kwh per day is 0.25kwh

Explanation:here, P=25W , V =220v

By using P=V×V÷R

We get, 25=220×220÷R

R=220×220÷25

R=1936 ohm

Now, by using E=P×t

=25×10

=250W

=250÷1000 kWh

=0.25 kWh

Hope it helps you☺️

All the best for your board result