An electric Lamp is mouked 26w 220v.
Iit is used four 10 hours. Calculate its
viesistance while glowing
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Answer:
Given that
Power=26W
Time=10h=10×60×60=36000sec
Energy=Power X Time
⇒Energy=26×36000=936000J
∵1kWh=3.6×10
6
J
Energy consumed in a day in unit of kWh =
3.6×10
6
936000
=0.26kWh
Hence energy consumed in a day is 0.26kWh
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