An electric lamp of 100 22, a toaster of resistance 50 12. and a waterfilter of resistance 500 2 are connected in parallel to a 220 V source.What is the resistance of an electric iron connected to the same sourcethat takes as much current as all three appliances, and what is thecurrent through it?
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Answer:
1/R = 1/R₁ + 1/R₂ + 1/R₃
1/R = 1/100 + 1/50 + 1/500
1/R = ( 5 + 10 + 1 )/500
1/R = 16/500
500/16 = R
Total Resistance (R) = 500/16 Ω
Explanation:
(2) According to ohm’s law the current through a conductor between two points is directly proportional to the voltage across the two points.
V ∝ I or V = IR
R is constant called resistance.
R = V/I
500/16 = 220/I
I = 220 × (16/500)
I = 7.04 A
Therefore, the resistance of the electric iron is 31.25 Ω and the current flowing through it is 7.04 A.
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