Question

An electric lamp of 100 ?, a toaster of resistance. 50 ?, and a water filter of resistance 500 ? are connected in parallel to a 220 V source. What is the resistance of an electric iron connected to the same source that takes as much current as all to the same source that takes as much current as all three appliances, and what is current through it

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Answer 1

Answer:

hii dear...

here is ur answer

Explanation:

In a parallel arrangement, the potential difference remain same but electric current is different.

Here, we have R₁ = 100 Ω, R₂ = 50 Ω and R₃ = 500 Ω

Total 1/R = 1/R₁ + 1/R₂ + 1/R₃

Total 1/R = 1/100 Ω + 1/50 Ω + 1/500 Ω

Total 1/R = ( 5 + 10 + 1 )/500

Total 1/R = 16/500

500/16 = Total R

Total Resistance = 500/16 Ω

Since, R = V/i

500/16 = 220/i

i = 220 × 16/500

i = 7.04 A

Here resistance and electric current used will be same.and therefore answers are :-

[1] 500/16 Ω OR

In Decimal, 31.25 Ω

[2] 7.04 A

Answer 2

$\large\bold{\underline{GIVEN :}}$

•R₁ = 100 Ω

•R₂ = 50Ω

•R₃ = 500 Ω

•V = 220v .

$\large\bold{\underline{TO \:FIND :}}$

•We need to find total resistance and current .

$\large\bold{\underline{SOLUTION :}}$

$\implies$Total resistance= 1/R = 1/R₁ + 1/R₂ + 1/R₃

$\implies$1/R = 1/100 Ω + 1/50 Ω + 1/500 Ω

$\implies$1/R = ( 5 + 10 + 1 )/500

$\implies$1/R = 16/500

$\implies$500/16 = Total Resistance

.°. $\red{\tt{Total \:resistance \:= 500/16 Ω}}$

$\implies$Since, R = V/I from ohm’s law

$\implies$500/16 = 220/I

$\implies$I = 220 × 16/500

.°. $\red{\tt{I = 7.04 \:A}}$