Question

an electric lamp of 100 Ohm,a toaster of resistance 50 Ohm,and a water filter of resistance 500 ohm are connected in parallel to a 220 V source.What is the resistance of an electic iron connected to the same source that takes as much current as all three appliances and what is the current through it​

Answer 1

Explanation:

Therefore total current os 7.04 Ampere

Answer 2

$\bf{\underline{\underline \green{AnswEr:-}}}$

In a parallel arrangement, the potential difference remain same but electric current is different.

Here, we have R₁ = 100 Ω, R₂ = 50 Ω and R₃ = 500 Ω

Total 1/R = 1/R₁ + 1/R₂ + 1/R₃

Total 1/R = 1/100 Ω + 1/50 Ω + 1/500 Ω

Total 1/R = ( 5 + 10 + 1 )/500

Total 1/R = 16/500

500/16 = Total R

Total Resistance = 500/16 Ω

Since, R = V/i

500/16 = 220/i

i = 220 × 16/500

i = 7.04 A

• Here resistance and electric current used will be same.and therefore answers are :-

• [1] 500/16 Ω OR In Decimal, 31.25 Ω
• [2] 7.04 A