An electric lamp of 100 ohm a toaster of resistance 50 ohm and a water filter of resistance 500 ohm are connected in parallel to a 220v source . What is the resistance of an electric iron connected to the same source that takes us much current as all three appliances , and what is the current through it ?
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Answer:
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Given parameters:
Resistance of electric lamp (R1) = 100 Ω
Resistance of toaster (R2) = 50 Ω
Resistance of water filter (R3) = 500 Ω
A potential difference of the source (V) = 220 V
To find
(1) Resistance of an electric iron
(2) The flow of electric current through the electric iron.
The three resistors are connected in parallel as shown in the below figure.
Solution
(1) Total resistance (R) can be calculated as shown below.
1/R = 1/R₁ + 1/R₂ + 1/R₃
1/R = 1/100 + 1/50 + 1/500
1/R = ( 5 + 10 + 1 )/500
1/R = 16/500
500/16 = R
Total Resistance (R) = 500/16 Ω
R = 31.25 Ω
(2) According to ohm’s law the current through a conductor between two points is directly proportional to the voltage across the two points.
V ∝ I or V = IR
R is constant called resistance.
R = V/I
500/16 = 220/I
I = 220 × (16/500)
I = 7.04 A
Therefore, the resistance of the electric iron is 31.25 Ω and the current flowing through it is 7.04 A.