An electric lamp of 100 ohms, toaster of resistance 50 ohms and a water filter of resistance 500ohms are connecte in parallel to a 220 V source. What is the resistance of an electric iron connected to the same sources takes as much current as all three appliances, and what is the current through it ?
Answers
Explanation:
1. in parallel i/ R is summ of All 1/Rs , so effective R is:
500 /16 ohms.
2. I = V/ R = 220×16/500=: ? 4.5 amps
Answer:
Explanation:
- Resistance of electric lamp = 100 Ω
- Resistance of toaster = 50 Ω
- Resistance of water filter = 500 Ω
- Voltage (V) = 220 V
- Appliances are connected in parallel
- Resistance of the electric iron
- Current through the electric iron if it takes as much current as the other three appliances.
→ Since the appliances are connected in parallel, we have to find the total resistance.
→ The total resistance when resistors are connected in parallel is given by,
→ Substituting the individual resistances,
R = 500/16 = 31.25 Ω
→ Hence resistance of the electric iron is 31.25 Ω
→ By Ohm's law we know that,
I = V/R
→ Substituting the datas we get the value of current (I)
I = 220/31.25
I = 7.04 A
→ Hence current flowing through the electric iron is 7.04 A
→ The total resistance when resistors are connected in series is given by,
→ The total resistance when resistors are connected in parallel is given by,