Question

An electric lamp of 100hm, a toaster resistance of of 50 oh and a water filter of resistance 500ohm are connected in series combination to a 220 volt source calculate totally resistance and current flowing through the cuicuit and p. D in electronic lamp and toaster. ​

Answer 1

Answer:

Given parameters:

Resistance of electric lamp (R1) = 100 Ω

Resistance of toaster (R2) = 50 Ω

Resistance of water filter (R3) = 500 Ω

Potential difference of the source (V) = 220 V

To find

(1) Resistance of an electric iron

(2) The flow of electric current through the electric iron.

The three resistors are connected in parallel as shown in the below figure.

Resistance 100 ohm, 50 ohm , 500 ohm connected in parallel

(1) Total resistance (R) can be calculated as shown below.

1/R = 1/R₁ + 1/R₂ + 1/R₃

1/R = 1/100 + 1/50 + 1/500

1/R = ( 5 + 10 + 1 )/500

1/R = 16/500

500/16 = R

Total Resistance (R) = 500/16 Ω

R = 31.25 Ω

(2) According to ohm’s law the current through a conductor between two points is directly proportional to the voltage across the two points.

V ∝ I or V = IR

R is constant called resistance.

R = V/I

500/16 = 220/I

I = 220 × (16/500)

I = 7.04 A

Therefore, the resistance of the electric iron is 31.25 Ω and the current flowing through it is 7.04 A.

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