Question

an electric lamp of 200 ohm and a toaster of 100 ohm are connected in parallel to a 200v electricity source a) what is the current passing through the electric iron?​

Answer 1

Given ,

An electric lamp of 200 ohm and a toaster of 100 ohm are connected in parallel to a 200 v electricity source

We know that , the equivalent resistance in parrallel combination is given by

$\sf \star \: \: \frac{1}{R} = \frac{1}{ R_{1}} + \frac{1}{ R_{2}} + ... + \frac{1}{ R_{n} }$

Thus ,

$\Rightarrow \sf \frac{1}{R} = \frac{1}{200} + \frac{1}{100} \\ \\ \Rightarrow \sf \frac{1}{R} = \frac{3}{200} \\ \\ \Rightarrow \sf R = \frac{200}{3} \\ \\ \Rightarrow \sf R = 66.5 \: \: ohm$

Now ,

$\sf \star \: \: Electric \: current \: (I) = \frac{v}{ R}$

Thus ,

$\Rightarrow \sf I = \frac{220}{66.5} \\ \\ \Rightarrow \sf I = 3.3 \: \: amp$

$\therefore \sf \bold{\underline{The \: current \: passing \: through \: the \: iron \: is \: 3.3 \: amp </p><p>}}$

Answer 2

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