Question

an electric lamp of 24 ohm and a conductor of 6 ohm are connected in parallel to a 12v battery calculate

(1) Total resistance
(2) Total current
(3) potential difference across the conductor

Answer 1

Total resistance=4.8 ohm
Total current=2.5A
It is connected in parallel so same p.d. will flows.

Answer 2

Answer:

1.$4.8\Omega$

2. 2.5 A

3. 12 V

Explanation:

The electric lamp is connected in parallel with the conductor, The net resistance is given by:

$R = \frac{R_1R_2}{ R_1+R_2}\\R_1=24\Omega \\R_2=6\Omega\\R = \frac{24\times6}{24+6} = 4.8\Omega$

Total current in the circuit:

From Ohm's Law

$I = \frac{V}{R}$

$I = {12V}{4.8\Omega}=2.5 A$

In a parallel circuit, the potential difference across each component is same. Thus, potential difference across the conductor = 12 V