Question

an electric lamp of 24 ohm and a conductor of 6ohm are connected in parallel to a 12 v battery calculate. 1 total resistance . 2.total current in circuit 3. potential difference across the conductor
step by step plz fast​

Answer 1

Explanation:

4.8 ohm

voltage = 12v

1) r = 4.8 ohm

2) v= ir

12/4.8= i

2.5A = i

3) v = ir

12/12= i

1A= i

12/24= i

0.5A = i

Answer 2

Answer:

The answer will be:

1.  4.8 ohm.

2. 2.5 A

3. 12 V

Explanation:

Given;

       Resistance of electric lamp = 24 ohm;

      Resistance of the conductor = 6 ohm;

     Potential Difference = 12 V;

1. Since the components are connected in parallel combination. Thus the total  resistance will be given as;

             1/Re = 1/R1 + 1/R2;

where, Re = total resistance or equivalent resistance;

           R1 = Resistance of lamp;

           R2 = Resistance of conductor;

Hence, 1/Re = 1/24 + 1/6;

                    = (1 + 4)/24;

                    = 5/24;

            Re = 24/5 ohm;

            Re = 4.8 ohm.

2. We know that;

            V = IR                                  (ohm's law)

    Thus, I = V/R

where, I = current

         V = potential difference

         R = resistance

Thus, Total current in circuit = V/R

                                               = (12)/(24/5)

                                                = 5/2

                                                = 2.5 A.

3. Since both the components (i.e. the lamp and the conductor) are in parallel combination, thus, they will have same potential difference across them that the whole circuit have.

Therefore,     Potential difference across the conductor = 12 V.

That's all.