An electric lamp of resistance 10 ohm and a conductor of resistance 2 ohm are in series connected to a 6v battery as shown in the circuit calculate the total resistance of the circuit
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An electric lamp of resistance 10 ohm and a conductor of resistance 2 ohm are in series connected to a 6v battery as shown in the circuit.The total resistance of the circuit is 12Ω
We know that, if two resistances, R1 and R2 are connected in series in a circuit, then the equivalent resistance in the circuit is given by:
R1 + R2
In the question, resistance of the lamp (R1) = 10 Ω
Also, resistance of the conductor (R2) = 2 Ω
So, equivalent resistance in the circuit = R1 + R2 = (10 + 2) Ω = 12Ω
Total resistance of the circuit is 12Ω .
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