Question

an electric lamp of resistance 100 ohm draws a current of 0.5A . find the line voltage​

Answer 1

Given :

• Resistance of the electric lamp = 100 Ω.

• Current flowing in the electric lamp = 0.5 A.

To find :

Voltage of the electric lamp.

Solution :

We know that , According to the ohm's law :

• Current flowing through a conductor is directly proportional to the Potential Difference on the ends of the conductor.

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀V ∝ I

Where :

• I = Current
• V = Voltage

Or ,

⠀⠀⠀⠀⠀⠀⠀⠀⠀V = IR

Where the constant, R is the resistance of the conductor.

Hence the formula we get for Potential Difference is :

$\boxed{\bf{V = IR}}$

Where :

• V = Potential Difference
• I = Current
• R = Resistance

Now using the ohm's law and Substituting the value in it , we get :

$:\implies \bf{V = IR}$

$:\implies \bf{V = 0.5 \times 100}$

$:\implies \bf{V = \dfrac{5}{10} \times 100}$

$:\implies \bf{V = \dfrac{1}{2} \times 100}$

$:\implies \bf{V = \dfrac{1}{1} \times 50}$

$:\implies \bf{V = 50}$

$\boxed{\therefore \bf{V = 50\:V}}$

Hence the Potential Difference of the electric lamp is 50 V.

Answer 2

• GIVEN:-

Resistance = 100 ohm

Current = 0.5 A

• To Find:-

Voltage.

• SOLUTION:-

According to Ohm's law,

$\huge\boxed{\sf{V=IR}}$

where v is voltage, I is current, R is resistance.

According to the question,

$\large\Longrightarrow{\sf{V=IR}}$

$\large\Longrightarrow{\sf{V=0.5\times100}}$

$\large\Longrightarrow{\sf{V=50.0}}$

$\large\Longrightarrow{\sf{V=50\:V}}$

$\large\blue\therefore\boxed{\sf{\blue{Potential\: Difference=50 \: V}}}$

• EXPLORE MORE:-

According to Ohm's Law, the current flowing in a conductor is directly proportional to the potential difference applied across its ends provided that the physical conditions and the temperature of the conductor remain constant.

If a current I flows in a conductor when the potential difference across its ends is V, then according to Ohm's law,

$\large\boxed{\sf{I\propto\:V}}$

or,

$\large\boxed{\sf{\frac{V}{I}= constant}}$

In this equation if we put the constant equal to R, the resistance of conductor. Then,

$\large\boxed{\sf{V=IR}}$