Question

an electric lamp of resistance 100 ohm, supplied with the potential difference of 2V and having current of 50A. calculate the power of the lamp​

Answer 1

P=VI

V=2

I=50

then P= 50×2 =100watt

Answer 2

Given,

Resistance (R)= 100 ohm

Potential difference (V) = 2V

Current (I) = 50 A

As we know that,

=> P = I^2 x R

=> P = (50 x 50 x 100) Watt

=> P = 250000 Watt

Now,

Convert into Kilo Watt:-

=> P = (250000/1000) KW

=> P = 250 KW

Hence, the power of Lamp = P = 250 KW.