Question

An electric lamp of resistance 20 ohm and a resistance of 4 ohm are connected in a series to a 6 v battery A. Find total resistance
B. Find the current flowing through the circuit
C. Find the potential difference across the resistance

Answer 1

Answer:

Explanation:

(a) The resistance of the electric lamp 1 = 20 Ω.

The resistance of the conductor connected in series 2 = 4 Ω.

The total resistance in the circuit

R = R1 + R2

R = 20 Ω + 4 Ω = 24 Ω

(b) The total potential difference across the two terminals of the battery V = 6 V.

By Ohm's law, the current through the circuit is given by

I = V/R

 = 6 V/24

 = 0.25 A

(c) On applying Ohm's law to the electric lamp and resistor separately, we get potential difference across the electric lamp

V1 = 20 Ω × 0.25 A = 5 V

and that across the conductor

V2 = 4 Ω × 0.25 A = 1 V.