Question

An electric lamp of resistance 20 S2 and a conductor of
resistance 4 12 are connected to a 6 V battery as shown in the
circuit. Calculate :

(d) power of the lamp.
​

Answer 1

Answer:

Given:

Voltage of battery, i.e. V = 6 V

Resistance of electric lamp, i.e.  = 20 ohm

Resistance for the conductor connected in series  = 4 ohm

Total Resistance R = = 20 + 4 = 24  

As we know, according to the ohm’s law,

I = V/R = 6/24 = 0.25 A

Potential difference V across electric lamp,

V = I + R1

V = 0.25 x 20

V = 5V