Question

An electric lamp of resistance 4 ohm is connected to a 6v battery in series find the total resistance and current through the circuit

Answer 1

the total resistance of the circuit =20Ω+4Ω=24Ω

b). The current through the circuit= current through the bulb= current through the conductor.

The current through the circuit= the voltage of the batteryvoltage applied.

the current through the circuit =246amp

The current through the circuit = 0.25amp

c). The potential difference across the lamp and the conductor.

(i) The potential difference across the electrical lamp =0.25×20=5volt

(ii) The potential difference conductor =0.25×4=1 volt

d).  Power can be calculated as current through the lampvoltage across the lamp

     power=0.255→20W.

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