An electric lamp r=20 ohm conductor 4 ohm connected 6 v battery
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An electric lamp, whose resistance is 20Ω and a conductor of 4Ω resistance are connected to a 6V battery Calculate A. The total resistance of the circuit = 20Ω + 4Ω =24 Ω B. The current through the circuit = current through the bulb = current through the conductor The current through the circuit = Voltage applied/ the voltage of the battery The current through the circuit = (6/24) amp The current through the circuit =0.25 amp C. The potential difference across the electric lamp and the conductor. The potential difference across the electric lamp = 0.25 ×20 = 5 volt The potential difference across the conductor = 0.25 × 4 = 1volt
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