An electric lamp which runs at 80 volt d.c. and consumes 10 ampere is connected to 100 volt, 50 Hz a.c. mains. Calculate the inductance of the choke required.
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Answer:
L= 1.9 * 10^-2 H
Explanation:
Here, V= 80V, I= 10A,
R= V I
= 80 *10
= 8Ω
E(subscript v)= 100V ,v= 50Hz, I(subscript v)= I= 10A ,L=?
If Z is impedance of lamp and choke coil,
then Z= E(subscript v) *I(subscript v)
= 100 *10
=100Ω
As R^2+X (subscript L)^2 =Z^2
∴X (subscript L )^2
=Z^2 - R^2 =100-64=36, X(subscript )L=6Ω
Now X(subscript L)=ωL=2πvL
∴L= X(subscript L) /2πv
= 6*7/ 2*22*50
=1.9*10^-2 H
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