Question

An electric lamp whose resistance is 10 ohm
and a conductor of 2 ohm resistance are
connected in series to a 6 V battery. The
total current through the circuit and the
potential difference across the electric lamp are​

Answer 1

Answer:

Given,

R= 10ohm &2 ohm

connected in series = 6 v

Now,

In series combination R1 + R2 = 10ohm +2ohm= 12ohm

I= V/R

I= 6v/12ohm

I= 0.5A

V= IR

V= 0.5× 10

V=5 v

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