Question

An electric lamp whose resistance is 20 12 and a conductor of 4 2 resistance
are connected in series to a 6V battery. Find the current through the circuit and
the potential difference across the electrical lamp and conductor.​

Answer 1

Given that :-

Voltage of the battery (V) = 6V

resistance of electric lamp $R_1$ = 20 Ω

Resistance series conductor $R_2$ = 4 Ω

To find :-

1. current through the circuit

2. potential difference across the electrical lamp and conductor

We Know that ,

to finding a current we need total resistance

the total resistance (R)=  $R_1+R_2$

Solution :-

Total resistance = $R_1+R_2$

                   R   =  20 + 4 Ω

                   R   = 24 Ω

Now,

by using Ohm 's law

$I=\frac{V}{R}$

$I = \frac{6}{24} A$

I = 0 .25A

Current  = 0.25 A

Now ,

potential difference across the lamp,

$V_1=IR_1$

    $= 0.25 * 20$ V

    $=5V$

potential difference across the conductor,

$V_2 = IR_2$

   $=0.25 * 4$

   = 1V

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May be the is helpful for you

Answer 2

Answer:

idk

Explanation: