An electric lamp, whose resistance is 20 Ω and a conductor of 4 Ω resistance are connected
to a 60 V battery in series.
a) Draw a circuit to represent.
b) What is the total resistance?
c) What is the potential difference across the electric lamp?
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Answered by
3
Here is your answer.
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Answered by
1
hey mate!! here is ur answers..
(a) is in attachment
(b) R=(20+4)ohm
=24 ohm
(c) I=v/R
I=60/24
I=15/6A or 2.5A
Now, p. d across the electric lamp:-
v=I.R
=(15/6.20)V
=50V
(a) is in attachment
(b) R=(20+4)ohm
=24 ohm
(c) I=v/R
I=60/24
I=15/6A or 2.5A
Now, p. d across the electric lamp:-
v=I.R
=(15/6.20)V
=50V
Attachments:
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