Question

An electric lamp whose resistance is 20 ohm and a conductor of 4 ohm resistance are connected to a 6 V battery. Calculate (a) the total resistance of the circuit, (b) the current through the circuit and (c) the potential difference across the electric lamp and conductor. ​

Answer 1

Answer:

answer is attached

hope it helps

Answer 2

Answer:

Given :-

Resistance of electrical lamp = 6 ohm

Resistance of conductor = 4 ohm

Power of battery = 6 Volt

To Find :-

Resistance

Total current

Solution :-

❶ Total Resistance

As they are connected to same battery, therefore.

R1 + R2=R1+R2

= 6 + 4=6+4

ohmReq=10ohm

Therefore total resistance = 10 ohm

❷ Total Current

As we know that potential difference is defined as the product of current and resistance.

Therefore,

\huge \fbox {V = IR}

V = IR

Here,

V = Potential difference

I = Current

R = Resistance

\sf \: 6 = i \times 106=i×10

\sf \: i = \dfrac{6}{10}i=

10

6

A∴Current=0.6A