An electric lamp whose resistance is 20 ohm and a conductor of 4 ohm are connected in series to 6v battery. Find the current through the circuit and the potential difference across the electric lamp and conductor
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Solution
a). the total resistance of the circuit =20Ω+4Ω=24Ω
b). The current through the circuit= current through the bulb= current through the conductor.
The current through the circuit= the voltage of the batteryvoltage applied.
the current through the circuit =246amp
The current through the circuit = 0.25amp
c). The potential difference across the lamp and the conductor.
(i) The potential difference across the electrical lamp =0.25×20=5volt
(ii) The potential difference conductor =0.25×4=1 volt
d). Power can be calculated as current through the lampvoltage across the lamp
power=0.255→20W.
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