Question

An electric lamp whose resistance is 20 Ohm and a conductor of 4 Ohm resistance are connected in series to a 6V battery as shown in figure. Then the total current flowing through the circuit is
A. 36A B. 0.6A C. 4A D. 0.25A​

Answer 1

Step-by-step explanation:

Given An electric lamp whose resistance is 20 Ohm and a conductor of 4 Ohm resistance are connected in series to a 6 V battery as shown in figure. Then the total current flowing through the circuit is

• Given battery voltage V = 6 V
• Resistance of electric lamp R1 = 20 ohms
• Conductor of resistance in series R2 = 4 ohms.
• So total resistance in the circuit R = R1 + R2
•                                                             = 20 + 4
•                                                               = 24 ohms.
• By using Ohm’s law we have,
•      Current through the circuit I = V/R
•                                                        = 6 / 24
•                                                       = ¼
•                                                       = 0.25 Amps
• Therefore total current flowing through the circuit will be 0.25 Amps.

Reference link will be

https://brainly.in/question/2445194

Answer 2

Answer:

0.25A

Step-by-step explanation:

v=6v

R1=20

R2=4

so

R1+R2

20+4=24

from ohm's law I=V/R

. 6/24

. ≈0.25A is your ans