Question

An electric lamp whose resistance is 30 2 and a conductor of 6 2 resistance are connected in series to 9V battery as shown in the figure. The total current flowing in the circuit is​

Answer 1

Answer:

0.5 A, 5 V

Explanation:

In series combination,

R=R  

Lamp

​

+R  

conductor

​

=10Ω+2Ω=12Ω

I=  

R

V

​

=  

12Ω

6v

​

=0.5A

⇒V  

Lamp

​

=IR=0.5×10=5V

Answer 2

Explanation:

The total resistance of the circuit

=30Ω+6Ω=36Ω

The current through the circuit= current through the bulb= current through the conductor.

The current through the circuit=

$\frac{voltage \: applied}{the \: voltage \: of \: the \: battery}$

The current through the circuit =

$\frac{9}{36} amp$

The current through the circuit = 0.25amp

Hope this helps you.

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