An electric lamp whose resistance is 30 ohm and a conductor of 6 ohm resistance are connected in series to 9V battery as shown in the figure the total current flowing in the circuit is
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Given : an electric lamp whose resistance is 30 ohm and the conductor of 6 ohm resistance are connected in a series of 9 volt battery
To Find : the total current flowing in the circuit is
Solution:
an electric lamp resistance is 30 Ω
Another resistance is 6 Ω
Both are in series
Hence total Resistance = 30 + 6 = 36 Ω
I = V/R
I = Current = ?
V = Voltage = 9 V
R = Resistance = 36 Ω
=> I = 9/36
=> I = 0.25A
total current flowing in the circuit is 0.25A
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