Question

an electric lamp whose resistance is 30 ohm and the conductor of 6 ohm resistance are connected in a series of 9 volt battery as shown in the figure the total current flowing in the circuit is​

Answer 1

Answer:

voltage= current x resistance

so current to= voltage/resistance

here voltage= 9v

resistance= 6+30=36 ohm

current= 9/36=0.25 ampere

Answer 2

Given :  an electric lamp whose resistance is 30 ohm and the conductor of 6 ohm resistance are connected in a series of 9 volt battery

To Find :  the total current flowing in the circuit is​

Solution:

an electric lamp   resistance is  30 Ω

Another  resistance is  6  Ω

Both are in series

Hence total Resistance = 30 + 6  = 36  Ω  

I = V/R

I = Current  = ?

V = Voltage  = 9 V

R = Resistance  =  36  Ω  

=> I = 9/36

=> I = 0.25A

total current flowing in the circuit is​ 0.25A

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