An electric lamp whose resistance is 40Ω and conductor of 8Ω resistance are connected in series to 12V battery in an electric circuit. Calculate the total resistance of the circuit and the current flowing through the circuit.
Answers
Answered by
2
Answer:
r net is 6
Step-by-step explanation:
ohm is volt upon ampere
). the total resistance of the circuit =20Ω+4Ω=24Ω
b). The current through the circuit= current through the bulb= current through the conductor.
The current through the circuit= Total Resistancevoltage applied.
the current through the circuit =246amp
The current through the circuit = 0.25amp
c). The potential difference across the lamp and the conductor.
(i) The potential difference across the electrical lamp =0.25×20=5volt
(ii) The potential difference conductor =0.25×4=1 volt
d). Power can be calculated as current through the lampvoltage across the lamp
power=0.255→20W.
Answered by
2
Answer:
Total resistance = 48Ω
and Curent flow = 0.25A
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