Question

an electric lamp whose resistance is 40 ohm and a conductor of 80 ohm resistance are connected to a 12 volt battery of series circuit calculate total resistance of the circuit the current through the circuit the potential difference across the electric lamp and conductor​

Answer 1

Answer:

a). the total resistance of the circuit =20Ω+4Ω=24Ω

b). The current through the circuit= current through the bulb= current through the conductor.

The current through the circuit=  

the voltage of the battery

voltage applied

​  

.

the current through the circuit =  

24

6

​  

amp

The current through the circuit = 0.25amp

c). The potential difference across the lamp and the conductor.

(i) The potential difference across the electrical lamp =0.25×20=5volt

(ii) The potential difference conductor =0.25×4=1 volt

d).  Power can be calculated as  

current through the lamp

voltage across the lamp

​  

 

    power=  

0.25

5

​  

→20W.