Question

an electric lamp whose resistance is 40 ohm and a conductor of 80 ohm resistance are connected to a 12 volt battery of series circuit calculate total resistance of the circuit the current through the circuit the potential difference across the electric lamp and conductor​

Answer 1

Answer:

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Answer 2

Answer:

Solution: (a)

Here, the resistors, i.e lamp and conductor are connected in series.

We know that equivalent or total resistance in series is given as-

RT = R1 + R2

Substituting the value of R1 and R2 in the formula we get-

RT = 20 + 4

RT = 24Ω

Thus, the total resistance of the circuit is 24 Ohm.

Solution: (b)

From Ohm’s law, we know that-

V=I×R

It can be rearranged for I as-

I=V/R

Putting the value of V and R we get-

I = 62/4 (∵R=RT)

I = 1/4

I = 0.25A

Thus, the current through the circuit is 0.25 Ampere.

Solution: (c) (i) The potential difference across the electric lamp.

From Ohm’s law, potential difference, V is given as-

V=I×R

Putting the value of I=0.25 and R=20 we get-

V=0.25×20

V=5V

(i) The potential difference across the conductor.

From Ohm’s law, potential difference, V is given as-

V=I×R

Putting the value of I=0.25 and R=4 we get-

V=0.25×4

V =1V

Solution: (d)

The formula of power is given as-

P=I2 × R

Putting the value of I=0.25 and R=20 we get-

P = (0.25)2×20

P = 0.0625×20

P = 1.25W

Explanation:

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Explanation: