an electric lamp whose resistance is 40 ohm and conductor is 8 ohm resistance are connected in series to 12v battery in an electric circuit. calculate the total resistance of the circuit and the current flowing through the circuit
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Answer:
Total R= 48 Ohm
Total Current= 1.8A
Explanation:
R1 and R2 are connected in series.
R1= 40 Ohm
R2= 8 Ohm
Therefore total resistance= R1+R2= 40+8= 48 Ohm
Total current= I1+I2
I1= V/R1= 12/40= 0.3
I2= V/R2= 12/8= 1.5
Therefore total current= 0.3+1.5= 1.8A
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